Mission Reliability Calculator R(t)
Probability equipment survives a mission without failure: R(t) = e^(−t/MTBF) for the constant-failure-rate model.
R(t) = e^(−t/MTBF) = e^(−168/2,000) = 91.9% (exponential model, constant failure rate). The chance the asset completes the mission without failure.
Field notes from maintenance practice
The defaults tell a useful story: a machine with 2,000 h MTBF asked to run a 168-hour (one-week) campaign survives with probability e^(−168/2000) ≈ 92% — meaning roughly one campaign in twelve hits a failure, despite 'two thousand hours MTBF' sounding generous. The exponential's counterintuitive arithmetic is exactly why this calculator earns its place: intuition consistently overestimates R(t).
Two cautions: the model is memoryless (a 5-year-old unit and a new one have identical R(t) — true only in the flat bathtub region, badly false in wear-out, where Weibull models apply); and mission reliability multiplies across series equipment — five independent 92% machines give 0.92⁵ ≈ 66% campaign success, the quantitative case for buffers and redundancy.
Sources & references
- O'Connor & Kleyner, Practical Reliability Engineering — exponential model and its limits
- MIL-HDBK-338 — reliability functions and mission analysis
Reliability statistics assume the constant-failure-rate (useful life) region — early-life and wear-out phases need different models (Weibull).
Mission Reliability Calculator R(t) for maintenance and reliability teams: Probability equipment survives a mission without failure: R(t) = e^(−t/MTBF) for the constant-failure-rate model. Free, private (everything runs in your browser) and ready for daily plant use.
About Mission Reliability Calculator R(t)
R(t) = e^(−λt) = e^(−t/MTBF): the probability a unit with constant failure rate completes a mission of length t without failing. Enter MTBF and the mission duration — a production campaign, a week between service windows, a batch run — and the calculator returns the survival probability.
How to use Mission Reliability Calculator R(t)
- 1Enter your operating data for the period (hours, failures, repair times or factor percentages).
- 2The result computes instantly with the standard formula shown in the worked example.
- 3Trend the number period over period — the direction matters more than any single value.
Why use Mission Reliability Calculator R(t)?
- ✓Probability equipment survives a mission without failure: R(t) = e^(−t/MTBF) for the constant-failure-rate model — computed instantly with the standard formula
- ✓100% free and unlimited, with no sign-up, login or paywall
- ✓Runs entirely in your browser — readings and asset data never leave your device
- ✓Niche-specific defaults and thresholds for reliability function, traceable to the cited standards
Frequently asked questions
What does a 92% mission reliability actually mean for planning?+
That ~1 in 12 such missions ends in an unplanned failure — so for 50 campaigns a year, budget ~4 failure events: spares, intervention crews, schedule slack. R(t) converts reliability from a feeling into a frequency you can provision against. If the consequence of failure is severe, either shorten the mission (mid-campaign service), raise MTBF, or add redundancy.
Why doesn't the machine's age appear in the formula?+
The exponential model assumes a constant failure rate — the flat middle of the bathtub curve — where failures arrive randomly regardless of age. It's a good approximation for electronics in mid-life and complex repairable systems, and a poor one during infant mortality or wear-out. If your failures cluster with age, fit a Weibull (shape β>1 means wear-out) instead of using this simple model.
How do I get mission reliability for several machines in series?+
Multiply the individual R(t) values if failures are independent: R_line = R₁ × R₂ × … . Series chains erode brutally (ten 99% units → 90.4%), parallel redundancy rescues: two parallel units each with R = 0.92 give 1 − (0.08)² ≈ 99.4% if either alone can carry the load. This is the math behind N+1 design.
Can I use this for a fleet instead of one machine?+
Yes, reframed: with a fleet of n units each having reliability R(t) for the mission, the expected number of failures is n × (1 − R(t)) and the probability of zero fleet failures is R(t)ⁿ. Twenty trucks at 95% weekly reliability → expect one failure per week (20 × 0.05) and only a 36% chance of a failure-free week. Plan the workshop accordingly.
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